I said it's real for 4th grade math
We used the "hockey stick" looking kinda thing for long division in 4th grade.
I said it's real for 4th grade math
We used the "hockey stick" looking kinda thing for long division in 4th grade.
8/2(2+2) distributed would be
(8/2*2) + (8/2*2)
You can't cherry pick what parts of the problem you want to "distribute".
Guess what the product is?
If a chicken and a half laid an egg and a half in a day and a half, what would the cost be for 11 2x4's and 3 pounds of doornails?
Look at Mr. High Brow getting his home improvement supplies from The Sharper Image$23.57
There were no variables in the original problem, so introducing them is a moot point. The original expression contained only integers, so the order of operations still applies.
Why would you get xy? It would simplify to x/y. (I can't seem to find a "divided by" symbol on my keyboard other than the slash.)[/QUOTE}
The implied multiplication they're talking about makes that expression 3 * x ÷ 3 * y, and according to them multiplication and division have equivalent priority and so are executed left to right.Thus 3x is divided by 3 to give x which is then multiplied by y to give xy, which is ... not right
100000(this thread) = The number of conversations just like this happening across America.
But once you introduce variable terms, the coefficient and the variable become one unit that you cannot separate willy-nilly. 6/2x is not (six divided by two) times x, or 3x, because you cannot separate the 2 from the x and only divide by the 2 (unless it specifically says (6/2)x. 6/2x is 6 divided by the 2x term, which we can simplfy to 3/x. Whole different ball game. Order of operations is still followed, but variable terms hold together as one unit unless there is a multiplication operator between the number and the variable. In this case, the number ceases to act as the coefficient because in the expression 6/2*x, the coefficient of x is 1.But I'm using your fave PEDMAS, but the answer appears to be ... wrong. Variables shouldn't matter, we're talking about order of operation
The implied multiplication they're talking about makes that expression 3 * x ÷ 3 * y, and according to them multiplication and division have equivalent priority and so are executed left to right. Thus 3x is divided by 3 to give x which is then multiplied by y to give xy, which is ... not right
But once you introduce variable terms, the coefficient and the variable become one unit that you cannot separate willy-nilly. 6/2x is not (six divided by two) times x, or 3x, because you cannot separate the 2 from the x and only divide by the 2 (unless it specifically says (6/2)x. 6/2x is 6 divided by the 2x term, which we can simplfy to 3/x. Whole different ball game. Order of operations is still followed, but variable terms hold together as one unit unless there is a multiplication operator between the number and the variable. In this case, the number ceases to act as the coefficient because in the expression 6/2*x, the coefficient of x is 1.
There are other forums?
But once you introduce variable terms, the coefficient and the variable become one unit that you cannot separate willy-nilly. 6/2x is not (six divided by two) times x, or 3x, because you cannot separate the 2 from the x and only divide by the 2 (unless it specifically says (6/2)x. 6/2x is 6 divided by the 2x term, which we can simplfy to 3/x. Whole different ball game. Order of operations is still followed, but variable terms hold together as one unit unless there is a multiplication operator between the number and the variable. In this case, the number ceases to act as the coefficient because in the expression 6/2*x, the coefficient of x is 1.